作者elelith (trapped)
看板Chemistry
標題[問題] enzyme kinetics
時間Tue May 16 08:53:54 2006
這題是有關suicide substrate的
Thre reaction scheme is
K1 K2
E+S <----> ES ----> ED
K'
In this case [Et]-[ED] = [E] + [ES], where [Et] is the initail starting conc.
of enzyme, [ED] is the conc. of dead enzyme, and [E] and [ES] are the conc. of
viable enzyme that are repectively free and substrate-bound.
a) Using the steady state approximation for [ES], derive an expression for the
rate of creation of [ED]. (d[ED]/dt)
d[ES]/dt= K1[E][S] - K'[ES] - K2[ES] = 0
[ES] = K1[E][S]/(K'+K1)
d[ED]/dt = K2 [ES]
這樣不知道對不對 跟d[ES]/dt好像沒關係 ￣ー￣；
第二題跟第三題問在什麼時候 d[ED]/dt會是fist order and zeroth order in [S]
first order when [S] is at low conc. and zeroth when [S] > [E]?
when the rate of production of [ED] is zeroth in [S], what will be the rate?
K2[ES]?
上面答案如果不對的還煩請指正Orz
謝謝
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1F：推 reckson1017:計算過程有小錯 05/16 13:25
2F：推 elelith:可以把錯的地方指出來嗎 謝謝 05/16 13:43
3F：推 reckson1017: [ES] = K1[E][S]/(K'+K2) 05/16 17:44