作者LuisSantos (^______^)
看板trans_math
標題Re: [考古] 92年 計算題
時間Mon Jun 18 19:11:13 2007
※ 引述《j19880706 (smallpig)》之銘言:
: Find the minimum of the function f(x,y,z)=xy+4yz+8xz
: subject to the constraint xyz=256
: (The existence of the minimum is suggested by the geometry of the problem.)
: 這題要怎麼算 要用微分嗎
: 麻煩大大教教我
: 謝謝您
令 g(x,y,z) = xyz - 256
F(x,y,z) = f(x,y,z) + (λ)(g(x,y,z))
= xy + 4yz + 8xz + (λ)(xyz - 256)
Fx = y + 8z + (λ)(yz) = 0
=> -y - 8z = (λ)(yz)
-y - 8z
=> λ = --------- ------(1)
yz
Fy = x + 4z + (λ)(xz) = 0
=> -x - 4z = (λ)(xz)
-x - 4z
=> λ = --------- ------(2)
xz
Fz = 4y + 8x + (λ)(xy) = 0
=> -4y - 8x = (λ)(xy)
-4y - 8x
=> λ = ---------- ------(3)
xy
(1) x y + 8z
----- => (---)(--------) = 1
(2) y x + 4z
=> (x)(y + 8z) = (y)(x + 4z)
=> xy + 8xz = xy + 4yz => 8xz = 4yz => y = 2x (z > 0) ------(4)
(2) y x + 4z
----- => (---)(---------) = 1
(3) z 4y + 8x
=> (y)(x + 4z) = (z)(4y + 8x)
=> xy + 4yz = 4yz + 8xz => xy = 8xz => y = 8z (x > 0) ------(5)
(4) x
----- => 1 = ---- => x = 4z
(5) 4z
x = 4z , y = 8z 代入 xyz = 256 得 (4z)(8z)(z) = 256
z^3 = 8 => z = 2 => x = 4z = 8 , y = 8z = 16
因此當 x = 8 , y = 16 , z = 2 時 ,
f(x,y,z) 有最小值
f(8,16,2) = (8)(16) + (4)(16)(2) + (8)(8)(2)
= 128 + 128 + 128 = 384
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※ 編輯: LuisSantos 來自: 61.66.173.21 (06/18 19:12)
1F:推 ahongyeh:這題用算幾不等式很快的!! ^^ 219.68.184.236 06/18 20:22
2F:推 bs1435:我剛用算幾不等式下去算,答案384沒錯125.226.235.179 06/18 21:12
3F:推 ahongyeh:這題目真好心!!竟然還提供建議的作法 ^^ 219.68.186.165 06/18 21:22