作者reckson1017 (GOD)
看板Chemistry
标题Re: [问题]普通化学或有机化学
时间Wed Apr 5 21:13:06 2006
※ 引述《kijhao (。)》之铭言：
: We can calculate the percentages of two isomers at equilibrium
: using the equation △E=-R*T*lnK .
: △E is the energy difference between isomers
: R is the gas constant
: T is the Kelvin temperature
: K is the equilibrium constant between isomers
: 请问若已知的数据有△E , R , T , K
: 那要怎麽代公式求存在的百分比?
: 题目如下:
: The energy difference of 3.8 (KJ/mol) between gauche and anti butance
: corresponds to an equilibrium constant Keq of approximately 1.9
: Calculate the percentage of each conformer at equilibrium.
: 感谢各位大大的解答
.......................不对就算了.................................
Ksp=1.9
若两者平衡
令a=b达到平衡
1-x=x
则1.9=x/(1-x)
求得解离常数
我觉得△E , R , T , K是用不到的
这是我的感觉拉
看看有没有强者来说说对不对
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1F：推 Obiwang:K就是K啦....不是Ksp... 04/05 23:00
2F：推 kijhao:谢谢你的解答^^ 04/06 21:08