作者onlyveritas ( 食梦者)
看板Chemistry
标题[问题]仪器分析讯号杂讯问题
时间Fri Mar 7 09:48:58 2014
中正101分析考古题第1题
Three replicate determinations of the signal for a standard solution of an
analyte at a concentration of 10.0 ppm gave values of 0.163, 0.157, and 0.161
(arbitrary units), respectively. The signal of 6 reagent blanks gave values
of 0.0016, 0.0021, 0.0018, 0.0023, 0.0017, and 0.0020. The signal of an
unknown sample was found to be 0.118.
(a)Calculate the concentration of the unknown sample.
(b)Estimate the detection limit of the analysis.
请高手解惑
谢谢
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◆ From: 106.1.93.211
1F：推 moonjay77:1) 7.32ppm 2) 0.0025ppm ?? 03/07 14:52
2F：→ onlyveritas:请问怎麽算出来的？ 03/07 16:18
3F：→ wanderchang:Skoog开起来看一下吧 03/07 20:14
4F：→ o810418:LOD是空白讯号+三倍标准差 03/07 21:32
5F：→ o810418:同楼上上，skoog数据处理看一下比较好 03/07 21:33