作者KOBEII (#81)
看板GMAT
标题Re: [计量]PP PS1 Q48
时间Fri Aug 29 11:07:59 2008
※ 引述《joepeggykimo (joepeggykimo)》之铭言：
: A certain city with a population of 132,000 is to be divided into 11 voting
: districts,and no district is to have a population that is more than 10 percent
: greater than the population of any other district.What is the minumum possible
: population that the least population distict could have?
: (A)10,700
: (B)10,800
: (C)10,900
: (D)11,000
: (E)11,100
: 上面答案是D 但是我算出来是C 所以想请各位帮忙
: 我的想法是132000/11=12000
: 而10%X132000=13200
: 如果答案为10900的话 12000-10900=1100 1100+12000=13100<13200
: 所以我选C 这是我想到的解法 好像有点怪@@
我的算法
X + 1.1X*10 = 132,000
12X = 132,000
X = 11,000
前提假设是其他十个区都比X区多10% 设X区的投票人数为X
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1F：→ joepeggykimo:恩恩我现在懂了 之前看错题目了 谢谢你啊 08/30 07:52