作者cmjer (民J)
看板MATLAB
标题Re: [讨论]矩阵分解 用for loop
时间Tue May 22 19:09:43 2012
A=magic(8);
n=1;
for i1=1:(8/2)
for i2=1:(8/2)
M{n}=A(2*(i1-1)+1:2*i1,2*(i2-1)+1:2*i2);
n=n+1;
end
end
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※ 编辑: cmjer 来自: 140.117.167.222 (05/22 19:47)
1F：→ simon0216117:感谢cmjer的解惑,让我开始对程式有信心了,感谢!感谢! 05/22 22:30