小弟我这学期修了系上开的MATLAB 是第一次接触这软体 最近上到了关於for跟while的回圈 课本上有个例题 是关於日期的计算 简单讲就是使用者输入一组年月日 然後程式会告诉你你输入的日期是当年度的第几天 例如:输入1/10/2012 程式就会告诉你是2012的第10天 然後我反正闲闲 回家都会照着课本 把课本的程式码打进去matlab当作练习 就在run的时候我发现 如果输入15/33/99999 程式还是会告诉我 那天是当年度的第398天 囧 但是没有15月也没有33号啊 翻了翻後面 也没有说要怎麽防呆 这章节是在说回圈 所以我在想是不是要在哪个地方加个for或while loop进去就可解决这问题了 有高手可以提点我吗 我贴一下程式码 clear all;close all;clc; % get day, month, and year to convert disp('This program calculates the day of year given the special date.'); month = input('Enter specified month (1-12): '); day = input('Enter specified day (1-31): '); year = input('Enter specified year (yyyy): '); % check for leap year, and add extra day if necessary if mod(year,400) == 0 leap_day = 1; % years divisible by 400 are leap years elseif mod(year,100) == 0 leap_day = 0; % other centuries are not leap years elseif mod(year,4) == 0 leap_day = 1; % otherwise every 4th year is a leap day else leap_day = 0; % other years are not leap years end % calculate day of year by adding current day to the % days in previous months. day_of_year = day; for ii = 1:month-1 % add days in months from January to last month switch (ii) case{1,3,5,7,8,10,12}, day_of_year = day_of_year + 31; case{4,6,9,11}, day_of_year = day_of_year + 30; case 2, day_of_year = day_of_year + 28 +leap_day; end end % tell user fprintf('The date %2d/%2d/%4d is day of year %d.\n', ... month,day,year,day_of_year); --

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