作者monemo13 (李孟李孟)
看板Math
标题[微积] 极限计算
时间Mon Jan 24 22:55:47 2011
1+sin(x-3π/2)
1. lim ═══════ = ?
x→π x-π
2
(x-π/4)
2. lim ═══ 2 = ?
x→π/4 (tanx-1)
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1F：推 jameschou :1.答案是0 , 2.答案是1/4 01/24 22:59
2F：→ monemo13 :为什麽呢? 01/24 22:59
3F：→ monemo13 :答案是对的 01/24 23:00
4F：推 jameschou :罗必达呀 分子分母同为0就分子分母都微分 01/24 23:01
5F：→ monemo13 :对吼...我太局限於章节了...谢谢！ 01/24 23:02
6F：→ theoculus :1+sin(x-3π/2) = sin((x-π)-π/2) - sin(-π/2) 01/24 23:04
7F：→ theoculus :tanx-1 = tanx - tan(π/4) 01/24 23:04
8F：→ jacky7987 :楼上方法好酷 01/24 23:36