作者simmy420 (洗米)
看板Math
标题[微积] 台大99
时间Sun Feb 6 15:03:31 2011
题目: Find the volume of the solid bounded by the surface x^2+3*y^2+z^2=1
想到要用极座标 x=rcosθ , y=rsinθ
(rcosθ)^2+3(rsinθ)^2+z^2=1
=> r^2(1+2(sinθ)^2)+z^2=1
=> z= ±√(1-r^2(1+2(sinθ)^2))
然後就卡住了...
请问该如何计算呢?
谢谢
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1F:推 G41271 :这不就是椭球吗 02/06 15:06
2F:→ simmy420 :阿...我懂了,谢谢 02/06 15:21