作者CxMacchi (Carael Macchiato)
看板Math
标题[机统] Exponential Distribution's CDF
时间Tue Mar 1 17:51:34 2011
根据机率课本已知
Pr[X < t] = 1 - exp(-λt)
现在如果改成已知 X1 X2 分别为独立产生的exponential random number (同λ)
请问 Pr[X1+X2 < t] 的机率该怎麽求呢
一开始想说用 Pr[X1<t]*Pr[X2<t] 後来仔细一想又觉得怪怪的
不好意思麻烦大家了
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《Sometimes Love Just Ain't Enough》 Yan-zi
"But there's a danger in loving somebody too much.
And its sad when you know it's your heart you can't trust.
There's a reason why people don't stay where they are.
Baby sometimes love just ain't enough."
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※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 140.116.177.6
1F：推 recorriendo :X1+X2是Gamma random variable 03/01 18:39
※ 编辑: CxMacchi 来自: 140.116.177.6 (03/01 18:46)
2F：→ CxMacchi :谢谢楼上 我再去翻翻书！ 03/01 18:54
3F：推 vicwk :或者叫Erlang也可以 03/01 19:03
4F：→ CxMacchi :谢谢，我找到Erlang的作法了 :) 03/02 12:33