作者zako1113 (那个人)
看板Math
标题[线代] 矩阵的问题
时间Sat Jul 21 16:46:05 2012
If A is a skew-symmetric real matrix, prove that (I+A) is invertible.
(Hint: show that (I+A)X = 0 cannot have non-zero solution X in R^n)
用书内的提示
(I+A)X = 0 for some non-zero X
=> AX = -X
=> -1 is an eigenvalue of A
请问之後要怎麽做呢?
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1F：推 armopen :因为 skew-sym. 矩阵的特徵值只可能 0 或 纯虚数. 07/21 18:13