作者WilsonKao (Sapere aude)
看板NTU-Exam
标题[试题] 97上 金必耀 普通化学甲上 期中考
时间Sun Jan 18 01:31:44 2009
课程名称︰普通化学甲上
课程性质︰外系生/高中预修班普通化学
课程教师︰金必耀
开课学院:理学院
开课系所︰化学系
考试日期(年月日)︰2008/11/14
考试时限(分钟):超过 120 分钟 (没有待到最後不知道)
是否需发放奖励金:否
(如未明确表示,则不予发放)
试题 :
https://ceiba.ntu.edu.tw/course/d0f3fa/content/midterm.pdf
(希腊符号自动换成拼音以球排版方便)
1.(10%) A chemist in a galaxy far, far away performed the Millikan oil drop
experiment and got the following results for the charge on various drops.
What is the charge of the electron in zirkombs?
2.56*10^(-12) zirkombs, 7.68*10^(-12) zirkombs
3.84*10^(-12) zirkombs, 6.40*10^(-12) zirkombs
2.(8%) In the Kjeldahl method for analysis of nitrogen in protein, the sample
is digested in concentrated sulfuric acid, converting the nitrogen to ammonium
sulfate (NH_4)_2SO_4. NaOH is then added, converting (NH_4)_2SO_4 to ammonia
gas NH_3 , which is distilled into a standard HCl solution, where the
neutralization reaction NH3 + HCl → NH4_Cl occurs. The unneutralized acid is
determined by titration. Find the percent nitrogen by mass in a 10.0 g protein
sample if the HCl concentration in 500.0 mL of acid solution is reduced from
0.2000 M to 0.0742 M in Kjeldahl analysis.
3.(8%) State, in general terms, under what conditions one may expect the
diffraction of matter waves to be important in determining the dynamics of a
particle, and under what conditions diffraction is unimportant.
4.(8%) de Broglie suggested that the electrons possess both the particle and wave
characters. The wavelength (lamda) of the moving particle can be calculated
from the relation wavelength = h/mv. Compute the de Broglie wavelengths of
(a) A hydrogen atom with a velocity of 10^3 m/s.
(b) An electron with an energy 0.05 eV.
5.(5%) Photons are emitted in the Lyman series as hydrogen atoms undergo
transitions from various excited states to the ground state. If ground-state
He^(+) ions are present in the gas, can they absorb these photons? Explain.
6.(10%) The equation referred to by Debye in response to Schrodinger’s lecture on de
Broglie waves is the classical wave equation. For describing a standing wave
psi(x) in one dimension, it is
(d^2 psi)/(dx)^2 + (4*pi^2/lambda)*psi = 0
where lambda is the wavelength of the standing wave. (For a fixed lambda, a
solution of this equation is the sine wave y = A*sin(2px/l).) Show that this
equation becomes a one-dimensional form of Schrodinger's wave equation:
(-h^2/8*m*pi^2)*((d^2 psi)/(dx)^2) + Vpsi = Epsi
when the generalized form of the de Broglie wavelength lambda for a particle
moving in the presence of a potential, V(x), is substituted into the classical
equation and some algebraic rearrangement is made.
7.(9%) Give the number of orbitals and their labels for all orbitals with
(a) n = 3
(b) n = 5, l = 1
(c) n = 2, l =1, m = ± 1
8.(8%) Sketch radial wave functions R_nl(r) and r^2|R_nl(r)|^2 for 1s, 2s, 3s
orbitals.
9.(10%) Sketch signed contour plots or boundary surfaces on appropriate axes
of the following orbitals: 2s, 2p_x, 3p_x. 3d_xy, 4d_x^2-y^2. Also write down
the numbers of radial and angular nodal planes for the corresponding orbitals.
10.(12%) Write down the electron configurations of following atoms or ions:
C, Mg, Kr, Sc, Cr, Ni^(2+).
11. Consider an universe in which the eletrons obey the Pauli exclusion
principle, but have an intrinsic spin angular momentum of 5/2 instead of 1/2.
Thus the spin orientations in space are 5/2, 3/2, 1/2, -1/2, -3/2, -5/2.
Label these states alpha, beta, gamma, delta, epsilon, zeta. In all other
ways the universe under consideration is like our own.
(a) Consider the helium atom, a two-electron system, in its ground state.
What is the degeneracy of this state? (5%)
(b) When electron-electron interaction is included, the degeneracy of these
states will be removed. Indicate the lowest-energy electron
configuration? (Hint: Assume that Hund's rule is still valid in this
universe.) (5%)
(c) List the charge on the nuclei of the first four inert gas atoms in the
universe under consideration. (5%)
Useful constants:
1. Planck constant: h = 6.62607*10^(-34) J*s
2. proton mass m_p = 1.672623*10^(-27) kg
3. electron mass me = 9.10938*10^(-31) kg
4. 1 eV= 1.60210*10^(-12) erg
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