作者papple23g (逆道者)
看板Python
标题Re: [问题] 列表中依据元素分组
时间Wed Dec 18 17:37:30 2019
list_ = ['1A', '7A', '7A-1A', '1A-7A', '1C', '3D', '3B', '3A-7B',
'1A-28A-3A','20A-7A-3A', '28A-7A-3A-1A', '7A-3A-1A-28A', '1A-7C-3A',
'7B-3A-1A', '3C-7A','7B-3NAV', '3B-7NAV', '20-7', '7']
#设置分数字典
score_dict={
'A':1,
'B':2,
'C':2,
'D':3,
}
#建立result字典(空字典)
result=dict()
#检查列表中的每个项目
for text in list_:
#若含有NAV或者不含有任何分数字典中的key值，则设分数为零
if ('NAV' in text) or all(key not in text for key in score_dict.keys()):
score=0
#否则，根据分数字典计算分数
else:
score=sum(text.count(key)*value for key,value in score_dict.items())
#更新result字典
result[score]=result.get(score,[])+[text]
print(result)
结果:
{0: ['7B-3NAV', '3B-7NAV', '20-7', '7'],
1: ['1A', '7A'],
2: ['7A-1A', '1A-7A', '1C', '3B'],
3: ['3D', '3A-7B', '1A-28A-3A', '20A-7A-3A', '3C-7A'],
4: ['28A-7A-3A-1A', '7A-3A-1A-28A', '1A-7C-3A', '7B-3A-1A']}
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