作者plover (戒赌中！)
看板trans_math
标题Re: 不动点
时间Tue Nov 8 00:17:18 2005
※ 引述《aacvbn (救我的普物阿~~(？o？))》之铭言：
: Let f:[0,1]-->[0,1] is a continuous function ,
: then there exists a point c (- [0,1]
: such that f(c)=1-c^(2)
: 谢谢
Consider g(x) = f(x) - (1 - x^2).
g(0) = f(0) - 1≦0,
g(1) = f(1) ≧ 0.
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※ 编辑: plover 来自: 140.112.218.142 (11/08 00:17)
1F：推 aacvbn:Got it.Thanks. 11/08 00:24