作者dreamroyc ()
看板trans_math
标题[积分]
时间Fri Mar 23 23:26:36 2007
Prove that,for even powers of sine,
pi/2 1*3*5*…(2n-1) pi
∫ sin^2n(x)=------------------ * ----
0 2*4*6*…2n 2
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◆ From: 61.230.2.97
※ 编辑: dreamroyc 来自: 61.230.2.97 (03/23 23:28)
※ 编辑: dreamroyc 来自: 61.230.2.97 (03/23 23:29)
※ 编辑: dreamroyc 来自: 61.230.2.97 (03/23 23:29)
※ 编辑: dreamroyc 来自: 61.230.2.97 (03/23 23:30)
1F：推 GayerDior:令t=2n如何?且I_t=∫(sinx)^t ,x=0~pi/2 61.229.145.39 03/23 23:33
2F：→ GayerDior:加油你会的!! 61.229.145.39 03/23 23:34
3F：推 dreamroyc:我试试看 谢谢你 61.230.2.97 03/23 23:39
4F：→ GayerDior:更正:且I_t=∫(sinx)^t dx ,x=0~pi/2 61.229.145.39 03/23 23:45
5F：推 dreamroyc:会不会用黎曼合比较好解? 61.230.2.97 03/23 23:49
6F：→ dreamroyc:老实说令2n=t 有点算不出来 61.230.2.97 03/23 23:50
7F：推 GayerDior:Integration By Part 加油你会的!!!! 61.229.145.39 03/23 23:56
8F：→ GayerDior:其实我懒ㄉ打= =而且我要睡ㄌ881 61.229.145.39 03/23 23:57
9F：推 dreamroyc:好的，我努力，感谢回覆。 61.230.2.97 03/23 23:57
10F：推 vu3cj0su3:reduction? 218.160.159.43 03/24 01:48