作者hergan (永保安康~)
看板trans_math
标题Re: [积分] p value
时间Tue Apr 10 23:57:15 2007
※ 引述《hushenpaul (适之)》之铭言:
: determine all values of p for which the improper integral converges
: 1
: ∫ 1/x^p dx
: 0
p>1 1/p-1
p<=1 diverge
why??
1 1
∫ 1/x^p dx = x^1-p/1-p] = 1^1-p/1-p p>1 1-p<0 => ans=1/p-1
0 0
同理p<=1 1-p>=0 diverge
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