作者les93 (刀疤凶狠羊咩咩)
看板trans_math
标题[微分] 原文题型报告
时间Mon Oct 22 02:03:39 2007
老师说要做这题原文题的报告
但是我实在摸不着头绪该怎办
麻烦各位大大帮我解答一下
回覆我信箱
感谢万分~
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It is estimated that X months from now. the population of a certain
community will be P(x)=x^2(x平方)+20x+8,000
a.At what rate will the population be changing with respect
to time 15 months from now?
b.By now much will thw population actually change during the 16th
months?
Solution
a.The rate of change of the population with respect to time is
the derivative of the population function.That is,
Rate of change = P'(x)=2x+20
The rate of change of the population 15 months from now will be
p'(15)= 2+(15)+20 = 50 people per month
b.The actual change in the population during the 16th month is the
difference between the population at the end 16 months and the
population at the end of 15 months. That is,
Change in population = P(16)-P(15) =8,576-8,525
= 51 people
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多谢各位
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