※ 引述《rath (concentrate)》之铭言： : xe^x : S ------- dx =? : (x+1)^2 : 感恩~ (x)(e^x) ∫----------- dx (x + 1)^2 e^x 令 y = ------- x + 1 (e^x)(x + 1) - (1)(e^x) 则 dy = ------------------------- dx (x + 1)^2 (x)(e^x) = ----------- dx (x + 1)^2 (x)(e^x) ∫----------- dy (x + 1)^2 = ∫1 dy = y + c (x)(e^x) = ----------- + c (x + 1)^2 --

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