作者kkgfdsaa (Jared)
看板trans_math
标题[积分] 一题重积分
时间Thu May 12 18:56:49 2011
Use a double integral to find the area of the region within both of the
circles r = cosθ and r = sinθ.
π
√2 π
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4
2 4 sinθ
为什麽不能这样列 2∫ ∫ r drdθ 而是要 2∫ ∫ r drdθ ?
0
sinθ 0 0
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※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 123.240.26.95
1F:推 newversion:r=√2/2 是一个半径为√2/2的圆哦! 114.32.100.4 05/13 20:06
2F:→ newversion:r 的范围由原点=0向外=sinθ括张 114.32.100.4 05/13 20:07